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NEW QUESTION: 1
AWSでいくつかの新しいアプリケーションを開発して実行する必要があり、Elastic BeanstalkとCloudFormationの両方が幅広いAWSリソースの展開メカニズムとして役立つことがわかっています。
Elastic BeanstalkとCloudFormationの違いを説明するとき、TRUEステートメントは次のうちどれですか？
A. CloudFormationでカスタムリソースを設計およびスクリプト化できます
B. Elastic Beanstalkは、アプリケーションを強化する関連リソースのグループを繰り返し予測可能に作成するタスクを自動化し、簡素化します。 CloudFormationはサポートしていません。
C. Elastic Beanstalkは、AWSリソースタイプの1つとしてAWS CloudFormationアプリケーション環境をサポートしています。
D. AWS Elastic Beanstalkには、テンプレート、JSONまたはYAML形式のテキストベースのファイルという2つの概念が導入されています
Answer: A
Explanation:
These services are designed to complement each other. AWS Elastic Beanstalk provides an environment to easily deploy and run applications in the cloud. It is integrated with developer tools and provides a one-stop experience for you to manage the lifecycle of your applications.
AWS CloudFormation is a convenient provisioning mechanism for a broad range of AWS resources. It supports the infrastructure needs of many different types of applications such as existing enterprise applications, legacy applications, applications built using a variety of AWS resources and container-based solutions (including those built using AWS Elastic Beanstalk).
AWS CloudFormation supports Elastic Beanstalk application environments as one of the AWS resource types. This allows you, for example, to create and manage an AWS Elastic Beanstalk- hosted application along with an RDS database to store the application data. In addition to RDS instances, any other supported AWS resource can be added to the group as well.
https://aws.amazon.com/cloudformation/faqs/

NEW QUESTION: 2
How can you generate a report that contains a detailed set of information about a specific enclosure including configuration and event logs?
A. Use Insight Display to save a configuration file to the USB key.
B. Use the show all command from the Onboard Administrator CLI.
C. Use HP SIM to save a configuration file.
D. Use HP System Management Homepage of a blade in bay 1.
Answer: B

NEW QUESTION: 3

IntStream stream = IntStream.of (1,2,3); IntFunction<Integer> inFu= x -> y -> x*y;//line n1 IntStream newStream = stream.map(inFu.apply(10));//line n2
newStream.forEach(System.output::print);

A. Replace line n1 with:
IntFunction<IntUnaryOperator> inFu = x -> y -> x*y;
B. Replace line n2 with:
IntStream newStream = stream.map(inFu.applyAsInt (10));
C. Replace line n1 with:
IntFunction<UnaryOperator> inFu = x -> y -> x*y;
D. Replace line n1 with:
BiFunction<IntUnaryOperator> inFu = x -> y -> x*y;
Answer: B

NEW QUESTION: 4
Eine Organisation hat festgestellt, dass Benutzer nicht autorisierte Websites mit anonymen Proxys besuchen.
Welches der folgenden ist das BESTE?
A. Analysieren Sie den IP-Verkehr (Internet Protocol) auf Proxy-Anforderungen
B. Entfernen Sie die Anonymität vom Proxy
C. Deaktivieren Sie den Proxyserver in der Firewall
D. Blockieren Sie die IP-Adresse (Internet Protocol) bekannter anonymer Proxys
Answer: C