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NEW QUESTION: 1
Lisa, a user, reports increased delays and timeouts when trying to reach several Internet sites.
Which of the following would MOST likely be used when investigating the problem at Lisa's workstation?
A. nslookup
B. arp
C. nbtstat
D. route
Answer: A

NEW QUESTION: 2
A company hosts a website on premises and wants to migrate it to the AWS Cloud The website exposes a single hostname to the internet but it routes its functions to different on-premises server groups based on the path of the URL The server groups are scaled independently depending on the needs of the functions they support The company has an AWS Direct Connect connection configured to its on-premises network What should a solutions architect do to provide path-based routing to send the traffic to the correct group of servers?
A. Route all traffic to an internet gateway Configure pattern matching rules at the internet gateway to route traffic to the group of servers supporting that path
B. Route all traffic to a Network Load Balancer (NLB) with target groups for each group of servers Use pattern matching rules at the NLB to route traffic to the correct target group
C. Route all traffic to an Application Load Balancer (ALB) Configure path-based routing at the ALB to route traffic to the correct target group for the servers supporting that path.
D. Use Amazon Route 53 as the DNS server Configure Route 53 path-based alias records to route traffic to the correct Elastic Load Balancer for the group of servers supporting that path
Answer: B

NEW QUESTION: 3



A. Option B
B. Option C
C. Option F
D. Option A
E. Option E
F. Option D
Answer: B
Explanation:
let's suppose it is a /20 then we would have addresses from 192.168.0.1 to 192.168.15.255 Now let's suppose it is a /21 then we would have addresses from 192.168.8.1 to 192.168.15.255 So both summaries encompass the networks we want to summarize but the second one is the most restrictive one as it only encompasses the networks we were asked to summarize and not others so it is the correct summary.
In fact just count the number of subnets which is 8 and find the exponent of 2 which is 8, that gives you
3 and to find out the summary mask just do /24 - 3 = /21.
if you make it in binary you'll find out the answer too:
the interesting octet is 3rd one so let's convert in binary.
8 0000 1000
9 0000 1001
10 0000 1010
11 0000 1011
12 0000 1100
13 0000 1101
14 0000 1110
15 0000 1111
I've bolded the bits in common there are 5 so 16+5=21 which is mask and address is 192.168.8.0