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NEW QUESTION: 1
あなたは、Employeeという名前のクラスを作成しています。クラスははEmployeeTypeという名前の文字列プロパティを公開します。次のコードセグメントは、Employeeクラスを定義します。（行番号は参考のために含まれるだけです。）

Employeeクラス内または、Employee classに由来するクラス内のコードによるだけでEmployeeTypeプロパティ値にアクセスし、変更する必要があります。
あなたは、EmployeeTypeの資産の実現が必要条件を満たすことを確実とする必要があります。
あなたは、どの二つアクションを行うべきですか？（各正解は完全なソリューションの一部を表します。2つを選択してください。）
A. Replace line 06 with the following code segment: protected set;
B. Replace line 03 with the following code segment: public string EmployeeType
C. Replace line 05 with the following code segment: protected get;
D. Replace line 03 with the following code segment: protected string EmployeeType
E. Replace line 06 with the following code segment: private set;
F. Replace line 05 with the following code segment: private get;
Answer: D,E
Explanation:
protected string EmpType { get; private set;}
This is a quite common way to work with properties within base classes.
Incorrect:
Not D: Cannot be used because of the internal keyword on line 03.

NEW QUESTION: 2
質問をドラッグアンドドロップ
IPv4ネットワークサブネットを左側から右側の正しい使用可能なホスト範囲にドラッグアンドドロップします

Answer:
Explanation:

Explanation:
This subnet question requires us to grasp how to subnet very well. To quickly find out the subnet range, we have to find out the increment and the network address of each subnet. Let's take an example with the subnet 172.28.228.144/18:
From the /18 (= 1100 0000 in the 3rd octet), we find out the increment is 64. Therefore the network address of this subnet must be the greatest multiple of the increment but not greater than the value in the 3rd octet (228). We can find out the 3rd octet of the network address is 192 (because 192 = 64 * 3 and 192 < 228) -> The network address is 172.28.192.0. So the first usable host should be 172.28.192.1 and it matches with the 5th answer on the right. In this case we don't need to calculate the broadcast address because we found the correct answer.
Let's take another example with subnet 172.28.228.144/23 -> The increment is 2 (as /23 = 1111
1110 in 3rd octet) -> The 3rd octet of the network address is 228 (because 228 is the multiply of 2 and equal to the 3rd octet) -> The network address is 172.28.228.0 -> The first usable host is
172.28.228.1. It is not necessary but if we want to find out the broadcast address of this subnet, we can find out the next network address, which is 172.28.(228 + the increment number).0 or
172.28.230.0 then reduce 1 bit -> 172.28.229.255 is the broadcast address of our subnet.
Therefore the last usable host is 172.28.229.254.

NEW QUESTION: 3
Which three elements can a job chain process involve? (Choose three)
A. a lightweight job
B. another chain
C. an event
D. a program
E. a schedule
Answer: A,B,E
Explanation:
Explanation/Reference:
Explanation:
Don't really understand the answer so far.
Defining Chain Steps
After creating a chain object, you define one or more chain steps. Each step can point to one of the following:
A Scheduler program object (program)
Another chain (a nested chain)
An event schedule, inline event, or file watcher