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NEW QUESTION: 1
Your company has a single Active Directory Domain Services (AD DS) forest with a single domain named contoso.com. All client computers run Windows 7. All client computer accounts are located in the Computers container in the contoso.com domain.
You discover that multiple client computers were automatically shut down because the security log was full.
You need to ensure that client computers are not shut down when the security log becomes full. What should you do?
A. Modify the event log policy settings in the Default Domain Controllers Policy Group Policy object (GPO).
B. Configure an Event Viewer subscription.
C. Modify the event log policy settings in the Default Domain Policy Group Policy object (GPO).
D. Increase the maximum log size.
Answer: C

NEW QUESTION: 2
You want to retain the record with the largest value in the TotalAmount column for each CustID and ProductType using a Remove Duplicates stage. How can this be accomplished?
A. Hash partition on CustID and ProductType. Sort on CustID, ProductType and TotalAmount
B. Hash partition on TotalAmount. Sort on CustID, ProductType and TotalAmount
C. Hash partition on ProductType. Sort on CustID, ProductType and TotalAmount
D. Hash partition on CustID, ProductType and TotalAmount. Sort on CustID, ProductType and TotalAmount
Answer: A

NEW QUESTION: 3
When specifying a job as CRITICAL what must also be specified at either the job, job stream, or run cycle level?
A. Latest start
B. UNTIL
C. DEADLINE
D. AT
Answer: C

NEW QUESTION: 4
View the exhibit and examine the structure of the EMPLOYEES table.

You want to select all employees having 100 as their MANAGER_ID manages and their manager.
You want the output in two columns: the first column should have the employee's manager's LAST_NAME and the second column should have the employee's LAST_NAME.
Which SQL statement would you execute?
A. SELECT m.last_name "Manager", e.last_name "Employee"FROM employees m JOIN employees eON m.employee_id = e.manager_idWHERE m.manager_id=100;
B. SELECT m.last_name "Manager", e.last_name "Employee"FROM employees m JOIN employees eON e.employee_id = m.manager_idWHERE m.manager_id=100;
C. SELECT m.last_name "Manager", e.last_name "Employee"FROM employees m JOIN employees eWHERE m.employee_id = e.manager_id AND e.manager_id=100
D. SELECT m.last_name "Manager", e.last_name "Employee"FROM employees m JOIN employees eON m.employee_id = e.manager_idWHERE e.manager_id=100;
Answer: D