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NEW QUESTION: 1
企業がビジネスクリティカルなアプリケーションをAWSに移行しています。これは、Oracleデータベースを使用する従来の3層Webアプリケーションです。データは転送中および保存中に暗号化する必要があります。データベースは12 TBのデータをホストします。
内部を介したソースOracleデータベースへのネットワーク接続が許可されており、会社は可能な限りAWSマネージドサービスを使用して運用コストを削減したいと考えています。 Web層とアプリケーション層内のすべてのリソースが移行されました。データベースには、いくつかのテーブルと、主キーのみを使用する単純なスキーマがあります。ただし、多くのバイナリラージオブジェクト（BLOB）フィールドが含まれています。ライセンスの制限により、データベースのネイティブレプリケーションツールを使用できませんでした。
アプリケーションの可用性への影響が最も少ないデータベース移行ソリューションはどれですか。
A. Amazon EC2インスタンスをプロビジョニングし、同じOracleデータベースソフトウェアをインストールします。サポートされているツールを使用して、ソースデータベースのバックアップを作成します。アプリケーションのメンテナンスウィンドウで、EC2インスタンスで実行されているOracleデータベースにバックアップを復元します。 Amazon RDS for Oracleインスタンスをセットアップし、AWSでホストされているデータベース間にインポートジョブを作成します。ジョブが完了したら、ソースデータベースをシャットダウンし、データベース接続をRDSインスタンスに切り替えます。
B. アプリケーションのメンテナンスウィンドウ中に、オンプレミスのOracleデータベースに圧縮されたフルデータベースバックアップを作成します。バックアップの実行中に、10 GbpsのAWS Direct Connect接続をプロビジョニングして、Amazon S3へのデータベースバックアップファイルの転送速度を上げ、メンテナンスウィンドウ期間を短縮します。 SSL / TLSを使用して、直接接続接続を介してファイルをコピーします。バックアップファイルが正常にコピーされたら、メンテナンスウィンドウを開始し、Amazon RDSでサポートされているツールを起動して、新しくプロビジョニングされたAmazon RDS for Oracleインスタンスに暗号化を有効にしてデータをインポートします。データが完全に読み込まれるまで待ち、データベース接続を新しいデータベースに切り替えます。直接接続接続を削除して、不要な料金を削減します。
C. Amazon RDS for Oracleインスタンスをプロビジョニングします。インターネットにアクセスできる仮想プライベートクラウド（VPC）サブネット内でRDSデータベースをホストし、RDSデータベースをソースデータベースの暗号化されたリードレプリカとして設定します。 SSLを使用して、2つのデータベース間の接続を暗号化します。 RDS ReplicaLagメトリックを監視して、レプリケーションパフォーマンスを監視します。アプリケーションのメンテナンスウィンドウ中に、オンプレミスデータベースをシャットダウンし、レプリケーションラグがなくなったら、アプリケーション接続をRDSインスタンスに切り替えます。リードレプリカをスタンドアロンデータベースインスタンスに昇格させます。
D. AWS DMSを使用して、オンプレミスのOracleデータベースとAWSでホストされているレプリケーションインスタンスの間でデータセットをロードして複製します。透過的データ暗号化（TDE）を有効にしてAmazon RDS for Oracleインスタンスをプロビジョニングし、レプリケーションインスタンスのターゲットとして構成します。カスタマー管理のAWS KMSマスターキーを作成して、レプリケーションインスタンスの暗号化キーとして設定します。
AWS DMSタスクを使用して、データをターゲットRDSインスタンスにロードします。アプリケーションのメンテナンスウィンドウの間、およびロードタスクが進行中のレプリケーションフェーズに達した後、データベース接続を新しいデータベースに切り替えます。
Answer: D
Explanation:
https://aws.amazon.com/blogs/apn/oracle-database-encryption-options-on-amazon-rds/ https://docs.aws.amazon.com/AmazonRDS/latest/UserGuide/Appendix.Oracle.Options.AdvSecurity.htm l (DMS in transit encryption) https://docs.aws.amazon.com/dms/latest/userguide/CHAP_Security.html

NEW QUESTION: 2
Which two statements about NEAT are true? (Choose two.)
A. NEAT supports standard ACLs on the switch port.
B. NEAT is supported on an EtherChannel port.
C. NEAT should be deployed only with autoconfiguration.
D. NEAT uses CISP (Client Information Signaling Protocol) to propagate client IP address.
E. NEAT is not supported on an EtherChannel port.
Answer: C,E
Explanation:
Restrictions for Network Edge Authentication Topology
---
NEAT is not supported on an EtherChannel port.
It is recommended that NEAT is only deployed with auto-configuration.
This feature does not support standard ACLs on the switch port.
Reference: http://www.cisco.com/en/US/docs/ios-xml/ios/sec_usr_8021x/configuration/152mt/sec-ieee-neat.html

NEW QUESTION: 3
Which of the following must you implement for high availability in an SAP HANA production system?
There are 3 correct answers to this question.
A. A name server on one active node
B. Index server processes on all nodes
C. Data replication to the standby nodes
D. Shared file system for all nodes
E. A statistics server on one active node
Answer: B,D,E

NEW QUESTION: 4
Examine the data in the CUST_NAME column of the CUSTOMERS table.

You want to extract only those customer names that have three names and display the * symbol in place of the first name as follows:

Which two queries give the required output?
A. SELECT LPAD(SUBSTR(cust_name, INSTR (cust_name ' ')),LENGTH(cust_name) - INSTR(cust_name, ' '), '*') "CUST NAME"FROM customersWHERE INSTR(cust_name, ' ',1,2)<>0;
B. SELECT LPAD(SUBSTR(cust_name, INSTR(cust_name, ' ')),LENGTH(cust_name),'*') "CUST NAME"FROM customersWHERE INSTR(cust_name, ' ',-1,2)<>0;
C. SELECT LPAD(SUBSTR(cust_name, INSTR(cust_name, ' ')),LENGTH(cust_name),'*') "CUST NAME"FROM customersWHERE INSTR(cust_name, ' ',1,2)<>0;
D. SELECT LPAD(SUBSTR(cust_name, INSTR (cust_name ' ')),LENGTH(cust_name) - INSTR(cust_name, ' '), '*') "CUST NAME"FROM customersWHERE INSTR(cust_name, ' ',1,-2)<>0;
Answer: B,C