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NEW QUESTION: 1



A. Option B
B. Option A
C. Option D
D. Option C
Answer: D
Explanation:
*The environment setup for tablespace encryption is the same as that for transparent data encryption. Before attempting to create an encrypted tablespace, a wallet must be created to hold the encryption key.
*Setting the tablespace master encryption key is a one-time activity. This creates the master encryption key for tablespace encryption. This key is stored in an external security module (Oracle wallet) and is used to encrypt the tablespace encryption keys.
*Before you can create an encrypted tablespace, the Oracle wallet containing the tablespace master encryption key must be open. The wallet must also be open before you can access data in an encrypted tablespace.
*Salt is a way to strengthen the security of encrypted data. It is a random string added to the data before it is encrypted, causing repetition of text in the clear to appear different when encrypted. Salt removes the one common method attackers use to steal data, namely, matching patterns of encrypted text.
*ALT | NO SALT By default the database appends a random string, called "salt," to the clear text
of the column before encrypting it. This default behavior imposes some limitations on encrypted columns: / If you specify SALT during column encryption, then the database does not compress the data in the encrypted column even if you specify table compression for the table. However, the database does compress data in unencrypted columns and encrypted columns without the SALT parameter.

NEW QUESTION: 2
Which Java Database Connectivity (JDBC) thin client version supports the use of HTTP proxy settings that does NOT support TCP to connect to Autonomous Data Warehouse?
A. Any version
B. 12c Release 2 onwards
C. 17.4 onwards
D. 18.1 onwards
Answer: B
Explanation:
https://docs.oracle.com/en/cloud/paas/autonomous-data-warehouse-cloud/user/connect-preparing.html#GUID-EFAFA00E-54CC-47C7-8C71-E7868279EF3B

NEW QUESTION: 3
画面上のフィールドのオンラインドキュメント（（F1）ヘルプ）はどこに作成しますか？
A. データ要素
B. ドメイン
C. テーブル
D. 構造
E. フィールド
Answer: A

NEW QUESTION: 4



A. patient p = new Patient ("Mike"); int f = pas.indexOf(P)
B. int f = ps.indexOf(p2);
C. int f = ps.indexOf (patient("Mike"));
D. int f = ps.indexOf {new patient ("Mike")};
Answer: B