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NEW QUESTION: 1
Which describes an aspect of Java that contributes to high performance?
A. Java prioritizes garbage collection.
B. Java monitors and optimizes code that is frequently executed.
C. Java automatically parallelizes code execution.
D. Java has a library of built-in functions that can be used to enable pipeline burst execution.
Answer: A
Explanation:
https://dzone.com/articles/how-to-tune-garbage-collection-in-java

NEW QUESTION: 2
Refer to the exhibit. An administrator is migrating a PBX telephony system to an IP Phone solution using a fixed numbering plan. The extension numbers and PSTN DIDs cannot be changed. Which of the following methods can be used in order to reach the individual extensions at Site B when called via the PSTN?

A. The administrator needs to map the last four digits in the DID to the extension numbers using translation rules.
B. The administrator can add a 1 to the DID for Site B to become 300-555-31xxx.
C. No changes are necessary because PSTN calls are preceded with access code 9.
D. The administrator needs to map the last four digits in the DID to the extension numbers and prefix a site code.
E. The administrator needs to map the last four digits in the DID to the extension numbers and prefix an intersite code.
Answer: A
Explanation:
Since the extension and PSTN DID is one and the same for the customer, no manipulation is required the Route Plan to reach individual extensions from PSTN DID

NEW QUESTION: 3
Sie sind Datenbankentwickler für eine Anwendung, die auf einem Microsoft SQL Server 2012-Server gehostet wird.
Die Datenbank enthält zwei Tabellen mit folgenden Definitionen:

Weltweite Kunden bestellen aus mehreren Ländern.
Sie müssen das Land anzeigen, aus dem jeder Kunde die meisten Bestellungen aufgegeben hat.
Welche Transact-SQL-Abfrage verwenden Sie?
A. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
VOM KUNDEN c
INNER JOIN
(SELECT Kundennummer, Versandland,
RANK () ÜBER (PARTITION NACH CustomerID
BESTELLUNG NACH BESTELLBETRAG DESC) ALS Rnk
FROM Bestellungen
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
WO o.Rnk = 1
B. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
VOM KUNDEN c
INNER JOIN
(SELECT Kundennummer, Versandland,
RANK () ÜBER (PARTITION NACH CustomerID
ORDER BY COUNT (OrderAmount) DESC) AS Rnk
FROM Bestellungen
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
WO o.Rnk = 1
C. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
VOM KUNDEN c
INNER JOIN
(SELECT Kundennummer, Versandland,
COUNT (OrderAmount) DESC) ALS OrderAmount
FROM Bestellungen
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
BESTELLEN NACH OrderAmount DESC
D. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
VON
(SELECT c.CustomerID, c.CustomerName, o.ShippingCountry,
RANK () ÜBER (PARTITION NACH CustomerID
ORDER BY COUNT (o.OrderAmount) ASC) AS Rnk
VOM KUNDEN c
INNER JOIN Bestellungen o
ON c.CustomerID = o.CustomerID
GROUP BY c.CustomerID, c.CustomerName, o.ShippingCountry) cs
WO Rnk = 1
Answer: B