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NEW QUESTION: 1
You create a client application by using Microsoft .NET Framework 3.5. The client application consumes a Windows Communication Foundation service that uses the netMsmqBinding binding.
The binding uses a private transactional queue named Library.
The following code fragment is part of the application configuration file.
(Line numbers are included for reference only.)
01 <endpoint binding="netMsmqBinding"
02 contract="ServiceReference.ILibrary"
04 />
You need to specify the address of the endpoint. Which attribute should you insert at line 03?
A. Address="net.msmq://localhost/private/transactional/Library"
B. Address="net.msmq://.\private$\Library"
C. Address=". \private$\Library"
D. Address="net.msmq://localhost/private/Library"
Answer: D
NEW QUESTION: 2
View the Exhibit and examine the structure of the ORDERS and CUSTOMERS tables.
Evaluate the following SQL command:
SQL> SELECT o.order_id, c.cust_name, o.order_total, c.credit_limit
FROM orders o JOIN customers c
USING (customer_id)
WHERE o.order_total > c.credit_limit
FOR UPDATE
ORDER BY o.order_id;
Which two statements are true regarding the outcome of the above query? (Choose two.)
A. It locks all the rows that satisfy the condition in the statement.
B. The locks are released after a DML statement is executed on the locked rows.
C. It locks only the columns that satisfy the condition in both the tables.
D. The locks are released only when a COMMIT or ROLLBACK is issued.
Answer: A,D
Explanation:
FOR UPDATE Clause in a SELECT Statement
Locks the rows in the EMPLOYEES table where job_id is SA_REP.
Lock is released only when you issue a ROLLBACK or a COMMIT.
If the SELECT statement attempts to lock a row that is locked by another user, the database waits until the row is available, and then returns the results of the SELECTstatement SELECT employee_id, salary, commission_pct, job_id FROM employees WHERE job_id = 'SA_REP' FOR UPDATE ORDER BY employee_id;
NEW QUESTION: 3
WebApp1という名前のAzure Webアプリを作成します。 WebApp1には、次の展示に示すオートスケール設定があります。
スケールアウトとスケールインのルールは、10分の期間と5分のクールダウン時間を持つように構成されています。
ドロップダウンメニューを使用して、図に示されている情報に基づいて各ステートメントを完了する回答の選択肢を選択します。
注:それぞれの正しい選択は1ポイントの価値があります。
Answer:
Explanation:
Explanation:
Box 1: one instance
Refer to scaling condition provided in the question, August 8, 2018 is outside the schedule of the scale condition 1, and Default instance count is 1.
Box 2: two instances
The default instance count is important because autoscale scales your service to that count when metrics are not available. Therefore, select a default instance count that's safe for your workloads.
The Default instance count of scale condition 1 is 4, and the Scale in rule decreases the count with 1.
So initial instance count before scale in condition met = 4
CPU utilization was at 15% for 60 mins so after first 10 mins ( The scale out and scale in rules are configured to have a duration of 10 minutes )instance count reduces by 1 hence after first 10 mins instance count is 4-1=3 Now cool down period is 5 mins , after first 15 mins instance count is 3 .
After next 15 mins , instance count will be 3-1=2.
After next 15 mins , instance count will be =2 because minimum instance count must be 2 , it can't get reduced beyond 2.
So after 60 mins instance count will be at 2.
Reference:
https://docs.microsoft.com/en-us/azure/azure-monitor/platform/autoscale-best-practices
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