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NEW QUESTION: 1
DRAG DROP

Answer:
Explanation:

Explanation:

Processing Delay: Coder delay is the time taken by the digital signal processor (DSP) to compress a block of PCM samples. This is also called processing delay (n). This delay varies with the voice coder used and processor speed. Serialization Delay: Serialization delay (n) is the fixed delay required to clock a voice or data frame onto the network interface. It is directly related to the clock rate on the trunk. Dejitter Buffer: Because speech is a constant bit-rate service, the jitter from all the variable delays must be removed before the signal leaves the network. In Cisco router/gateways this is accomplished with a de-jitter (n) buffer at the far-end (receiving) router/gateway. The de-jitter buffer transforms the variable delay into a fixed delay. It holds the first sample received for a period of time before it plays it out. This holding period is known as the initial play out delay. DSP Delay: The time the packet spends inside the DSP is known as DSP Delay. Sampling, Encoding, Decoding etc. takes place inside the DSP. Queuing Delay: After the compressed voice payload is built, a header is added and the frame is queued for transmission on the network connection. Voice needs to have absolute priority in the router/gateway. Therefore, a voice frame must only wait for either a data frame that already plays out, or for other voice frames ahead of it. Essentially the voice frame waits for the serialization delay of any preceding frames in the output queue. Queuing delay (Bn) is a variable delay and is dependent on the trunk speed and the state of the queue. There are random elements associated with the queuing delay. Propagation Delay: Caused by the length a signal must travel via light in fiber or electrical impulse in copper-based networks
http://www.cisco.com/en/US/tech/tk652/tk698/technologies_white_paper09186a00800a8993.shtml

NEW QUESTION: 2
Sie müssen die Anwendungsanforderungen für App1 erfüllen.
Welche drei Aktionen sollten Sie ausführen? Jede richtige Antwort ist Teil der Lösung.
HINWEIS: Jede richtige Auswahl ist einen Punkt wert.
A. Konfigurieren Sie im Microsoft 365 Admin Center die Einstellungen für den Software-Download.
B. Installieren Sie auf einem lokalen Server den Assistenten für die Hybridkonfiguration.
C. Laden Sie auf einem lokalen Server den Microsoft AAD Application Proxy-Connector herunter und installieren Sie ihn.
D. Konfigurieren Sie im Azure Active Directory-Verwaltungscenter die Einstellungen für die Anwendungs-URL.
E. Fügen Sie im Azure Active Directory-Verwaltungscenter eine Unternehmensanwendung hinzu.
Answer: C,D,E
Explanation:
Explanation
* An on-premises web application named App1 must allow users to complete their expense reports online.
Application Proxy is a feature of Azure AD that enables users to access on-premises web applications from a remote client. Application Proxy includes both the Application Proxy service which runs in the cloud, and the Application Proxy connector which runs on an on-premises server. Azure AD, the Application Proxy service, and the Application Proxy connector work together to securely pass the user sign-on token from Azure AD to the web application.
In this question, we need to add an enterprise application in Azure and configure a Microsoft AAD Application Proxy connector to connect to the on-premises web application (App1).
Reference:
https://docs.microsoft.com/en-us/azure/active-directory/manage-apps/application-proxy#how-application-proxy-

NEW QUESTION: 3
A custom Visualforce component. All custom component definitions must be wrapped inside a single
<apex:component> tag.
A. apex:includeScript
B. apex:commandLink
C. apex:dataTable
D. apex:component
Answer: D

NEW QUESTION: 4
Given:
public class Product {
int id; int price;
public Product (int id, int price) {
this.id = id;
this.price = price;
}
Public String toString () { return id + ":" + price;)
}
and the code fragment:
List<Product> products = new ArrayList <> (Arrays.asList(new Product(1, 10),
new Product (2, 30),
new Product (3, 20));
Product p = products.stream().reduce(new Product (4, 0), (p1, p2) -> {
p1.price+=p2.price;
return new Product (p1.id, p1.price);});
products.add(p);
products.stream().parallel()
.reduce((p1, p2) - > p1.price > p2.price ? p1 : p2)
.ifPresent(System.out: :println);
What is the result?
A. 4:60
B. 4:0
C. 4:602:303:201:10
D. The program prints nothing
E. 2:30
Answer: C