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NEW QUESTION: 1
Your company is designing its public network. The network will use an IPv4 range of 131.107.40.0/22. The network must be configured as shown in the following exhibit.

You need to configure subnets for each segment.
Which network addresses should you assign?
A. Segment A: 131.107.40.0/23 Segment B: 131.107.42.0/24 Segment C: 131.107.43.0/25 Segment D: 131.107.43.128/27
B. Segment A: 131.107.40.0/23 Segment B: 131.107.41.0/24 Segment C: 131.107.41.128/25 Segment D: 131.107.43.0/27
C. Segment A: 131.107.40.128/23 Segment B: 131.107.43.0/24 Segment C: 131.107.44.0/25 Segment D: 131.107.44.128/27
D. Segment A: 131.107.40.0/25 Segment B: 131.107.40.128/26 Segment C: 131.107.43.192/27 Segment D: 131.107.43.224/30
Answer: A
Explanation:
We should know right away our first subnet would not use a /25 mask, as this is only gives our largest segment 126 hosts, but we need 280. That's one answer eliminated.
The remaining options all seem plausible at first glance, since a /23 subnet allows 510 hosts, a /24 subnet = 254, a /25 subnet = 126 hosts and /27 = 30 hosts. This allows us enough room for the segments specified in the diagram.
What we have to do is figure out which subnets are valid ranges.
Starting with SegmentA, 131.107.40.0/23 gives a host range of 131.107.40.1 - 131.107.41.254.
This means our next range (SegmentB) should start with 131.107.42, but only one answer has this. That automatically eliminates the rest!
Reference: http://www.gestioip.net/cgi-bin/subnet_calculator.cgi

NEW QUESTION: 2
Which of the following are examples of sandboxing implementations?
A. HTML5 "sandbox" attribute for use with iframes
B. Google Chromium sandboxing
C. HTML CSS and JavaScript sandboxing
D. Java Virtual Machine (JVM) sandboxing
Answer: A,B,D

NEW QUESTION: 3
会社はDynamics365Salesを使用しています。 Power Appsを使用して、営業チームのメンバーが顧客、リード、および商談のデータを入力できるキャンバスアプリを作成することを計画しています。
営業チームのメンバーは、デスクトップ、ラップトップ、タブレット、およびモバイルデバイスから情報を入力できる必要があります。
すべての営業担当者は、同じフォーム、ビュー、およびレポートにアクセスする必要があります。
作成する必要のあるPowerAppsの最小数はいくつですか?
A. 0
B. 1
C. 2
D. 3
Answer: C


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