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NEW QUESTION: 1
회사는 웹 서버, 응용 프로그램 서버 및 데이터베이스 서버로 구성된 3 계층 웹 응용 프로그램을 만들고 있습니다. 애플리케이션은 배송되는 패키지의 GPS 좌표를 추적합니다. 응용 프로그램은 0-5 초마다 데이터베이스를 업데이트합니다.
추적은 사용자가 패키지 상태를 확인하기 위해 가능한 빨리 읽어야 합니다. 어떤 날에는 몇 개의 패키지만 추적 될 수 있는 반면 다른 날에는 수백만 개의 패키지가 추적 될 수 있습니다. 추적은 추적 ID 고객 ID 및 주문 ID 주문으로 검색 할 수 있어야 합니다. 1 개월 이상은 추적 할 수 없습니다.
최소한의 소유 비용으로 이를 달성하기 위해 솔루션 설계자는 무엇을 권장해야 합니까?
A. 프로비저닝 된 IOPS (PIOPS)와 함께 Amazon RDS 예약 인스턴스를 사용합니다. PIOPS가 초과 될 때 알림을 보내도록 Amazon CloudWatch 경보를 활성화합니다. 필요에 따라 PIOPS를 늘리거나 줄입니다.
B. 글로벌 보조 인덱스와 함께 Amazon DynamoDB를 사용합니다. DynamoDB 테이블 및 글로벌 보조 인덱스에서 Auto Scaling을 활성화합니다. DynamoDB 테이블에서 TTL을 활성화합니다.
C. Amazon DynamoDB 사용 DynamoDB 테이블에서 Auto Scaling을 활성화합니다. 1 개월이 지난 항목에 대한 자동 삭제 스크립트를 예약합니다.
D. 프로비저닝 된 IOPS (PIOPS)와 함께 Amazon RDS 온 디맨드 인스턴스를 사용합니다. PIOPS가 초과 될 때 알림을 보내도록 Amazon CloudWatch 경보를 활성화합니다. 필요에 따라 PIOPS를 늘리거나 줄입니다.
Answer: B

NEW QUESTION: 2
What happens after issuing the command vi without any additional parameters?
A. vi starts and loads the last file used and moves the cursor to the position where vi was when it last exited.
B. vi starts and opens a new file which is filled with the content of the vi buffer if the buffer contains text.
C. vi starts and requires the user to explicitly either create a new or load an existing file.
D. vi starts in command mode and opens a new empty file.
E. vi exits with an error message as it cannot be invoked without a file name to operate on.
Answer: D

NEW QUESTION: 3



A. CustNo
B. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN tblLoanAcct L ON D.CustNo
C. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
D. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT CustNoFROM tblLoanAcct) R
E. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
F. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
G. SELECT COUNT (DISTINCT D.CustNo)FROM tblDepositAcct D, tblLoanAcct LWHERE D.CustNo
H. CustNoWHERE D.CustNo IS NULL
I. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT CustNoFROM tblLoanAcct) R
J. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL OR L.CustNo IS NULL
Answer: J
Explanation:
Explanation
SQL Server provides the full outer join operator, FULL OUTER JOIN, which includes all rows from both tables, regardless of whether or not the other table has a matching value.
Consider a join of the Product table and the SalesOrderDetail table on their ProductID columns. The results show only the Products that have sales orders on them. The ISO FULL OUTER JOIN operator indicates that all rows from both tables are to be included in the results, regardless of whether there is matching data in the tables.
You can include a WHERE clause with a full outer join to return only the rows where there is no matching data between the tables. The following query returns only those products that have no matching sales orders, as well as those sales orders that are not matched to a product.
USE AdventureWorks2008R2;
GO
-- The OUTER keyword following the FULL keyword is optional.
SELECT p.Name, sod.SalesOrderID
FROM Production.Product p
FULL OUTER JOIN Sales.SalesOrderDetail sod
ON p.ProductID = sod.ProductID
WHERE p.ProductID IS NULL
OR sod.ProductID IS NULL
ORDER BY p.Name ;
References: https://technet.microsoft.com/en-us/library/ms187518(v=sql.105).aspx

NEW QUESTION: 4
Who owns the data from regional system?
Please choose the correct answer.
Response:
A. BDS layer
B. BW workspace layer
C. Agile data mart layer
D. Open layer
Answer: C