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NEW QUESTION: 1
次のAzureファイル共有を含むAzureサブスクリプションがあります。
次のオンプレミスサーバーがあります。
Sync1という名前のストレージ同期サービスと、Group1という名前のAzure File Syncグループを作成します。 Group1はshare1をクラウドエンドポイントとして使用します。
Server1とServer2をSync1に登録します。 Server1のD：\ Folder1をGroup1のサーバーエンドポイントとして追加します。
次の各文について、文が真の場合は「はい」を選択します。それ以外の場合は、[いいえ]を選択します。
注：それぞれの正しい選択には1ポイントの価値があります。

Answer:
Explanation:

Explanation

Box 1: No
Group1 already has a cloud endpoint named Share1.
A sync group must contain one cloud endpoint, which represents an Azure file share and one or more server endpoints.
Box 2: Yes
Yes, one or more server endpoints can be added to the sync group.
Box 3: Yes
Yes, one or more server endpoints can be added to the sync group.
References:
https://docs.microsoft.com/en-us/azure/storage/files/storage-sync-files-deployment-guide

NEW QUESTION: 2
ABC Corp. has the following Organization Structure:
1. Legal Entity: A
2. Operating Units: B and C
3. Balancing Entities: 10, 20, and 30
Identify three correct statements regarding the Balancing Entity. (Choose three.)
A. Balancing Entities can be automatically secured at the Legal Entity level.
B. Balancing Entities can be secured at the Operating Unit level through Security Rules.
C. Each Balancing Entity must balance within itself.
D. There can be multiple Balancing Entities within an Operating Unit.
E. Balancing Entity is the lowest postable unit in the Chart of Accoutns.
Answer: B,C,D

NEW QUESTION: 3
どのオプションがコンテンツ検査プロセスの一部ですか？
A. Packet forwarding process
B. SSL Proxy re-encrypt
C. IPsec tunnel encryption
D. Packet egress process
Answer: B
Explanation:
http://live.paloaltonetworks.com//t5/image/serverpage/image-id/12862i950F549C7D4E6309

NEW QUESTION: 4
Given:
1.import java.util.*;
2.public class Example {
3.public static void main(String[] args) {
4.// insert code here
5.set.add(new Integer(2));
6.set.add(new Integer(1));
7.System.out.println(set);
8.}
9.}
Which code, inserted at line 4, guarantees that this program will output [1, 2]?
A. Set set = new TreeSet();
B. Set set = new HashSet();
C. Set set = new LinkedHashSet();
D. List set = new SortedList();
E. Set set = new SortedSet();
Answer: A