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NEW QUESTION: 1
展示を参照してください。

データを形成するJSON構文は何ですか？
A. Name', 'Bob Johnson,' 'Age', 76, 'Alive', true, 'favourite Foods' 'Cereal Mustard', 'Onions'}
B. Name", "Bob Johnson", "Age": Seventysix, "Alive" true, "favourite Foods" ,[Cereal" "Mustard"
"Onions"}}
C. Name: Bob, Johnson, Age: 76, Alive: true, Favourite Foods. [Cereal, "Mustard", "Onions}}
D. Name", "Bob Johnson", "Age", 76, "Alive", true, "favourite Foods", ["Cereal, "Mustard", Onions"}}
E. {"Name":"Bob Johnson","age":76,"alive":true,"favorite
foods":["Cereal","Mustard","Onions"]}correct
Answer: E
Explanation:
Explanation
JSON data is written as name/value pairs.
A name/value pair consists of a field name (in double quotes), followed by a colon, followed by a value:
"name":"Mark"
JSON can use arrays. Array values must be of type string, number, object, array, boolean or null.
For example:
{
"name":"John",
"age":30,
"alive":true,
"cars":[ "Ford", "BMW", "Fiat" ]
}

NEW QUESTION: 2
You develop a Windows Communication Foundation (WCF) service that interacts with Microsoft Message Queuing (MSMQ).
The service requires sessions. You need to create a custom binding that enables messages sent to the queue to be viewed when you are using a listener tool.
Which binding elements should you use?
A. textMessageEncoding and msmqIntegrationTransport in this order
B. msmqIntegrationTransport and textMessageEncoding in this order
C. textMessageEncoding and msmqTransport in this order
D. msmqTransport and textMessageEncoding in this order
Answer: C

NEW QUESTION: 3
ClearPassの外部認証サーバーとしての汎用LDAPサーバーの構成について正しい説明はどれですか。 （3つ選択してください。）
A. 管理者は、LDAPサーバーから取得した属性の選択をカスタマイズできます。
B. LDAPブラウザーを使用してベースDNを検索できます。
C. 汎用LDAPブラウザーを使用してベースDNを検索できます。
D. ClearPassでは、最大1つの汎用LDAPサーバーを構成できます。
E. バインドDNは、administrator @ domain形式にすることができます。
Answer: A,B,C

NEW QUESTION: 4
Which changes, introduced independently, will allow the code to compile and display "one" "eight" "nine"
"ten"? Choose all that apply
#include <iostream>
#include <map>
#include <string>
using namespace std;
class A {
int a;
public:
A(int a):a(a){}
int getA() const { return a;}
/* Insert Code Here 1 */
};
/* Insert Code Here 2 */
int main(){
int t[] ={ 3, 4, 2, 1, 6, 5, 7, 9, 8, 10 };
string s[] = {"three", "four", "two", "one", "six","five", "seven", "nine","eight","ten"}; map<A, string> m;/* Replace Code Here 3 */ for(int i=0; i<10; i++) { m.insert(pair<A,string>(A(t[i]),s[i]));
}
m.erase(m.lower_bound(2),m.upper_bound(7));
map<A, string>::iterator i=m.begin(); /* Replace Code Here 4 */
for( ;i!= m.end(); i++) {
cout<<i?>second<<" ";
}
cout<<endl;
return 0;
}
A. operator int() const { return a;} inserted at Place 1
B. struct R { bool operator ()(const A & a, const A & b) { return a.getA()<b.getA();} }; inserted at Place 2 replacing line marked 3 with map<A, string, R> m; replacing line marked 4 with map<A, string,R>::iterator i=m.begin();
C. bool operator < (const A & b) const { return b.a<a;} inserted at Place 1
D. bool operator < (const A & b) const { return a<b.a;} inserted at Place 1
Answer: A,B,D