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NEW QUESTION: 1
What happens when you attempt to compile and run the following code?
#include <cstdlib>
#include <iostream>
using namespace std;
float* sum(float a,float b);
float* sum(float a,float b)
{
float *f = new float;
*f = a+b;
return f;
}
int main()
{
float a,b,*f;
a = 1.5; b = 3.4;
f = sum(a,b);
cout<<*f;
return 0;
}
A. It prints: 5
B. It prints: 4.9
C. It prints: 0
D. It prints: 4
Answer: B

NEW QUESTION: 2
As a network technician, you should know the VoIP network components well. Which one
of the following components can provide the CAC, bandwidth control and management, and address translation?
A. Gatekeeper
B. Gateway
C. Call agent
D. MCU
Answer: A

NEW QUESTION: 3
Oracle 12cマルチテナントコンテナーデータベース（CDB）には、複数のプラガブルデータベース（PDB）が含まれています。
PDB HR_PDBでは、共通ユーザーC ## ADMINとローカルユーザーB_ADMINにはCONNECT権限のみがあります。
CREATE ANY TABLE特権とSELECT ANY TABLE特権を使用して、共通ロールC ## ROLE1を作成します。
次に、コマンドを実行します。
SQL> GRANT c##role1 TO c##admin CONTAINER=ALL>;
SQL> CONN sys/oracle@HR_PDB as sysdba
SQL> GRANT c##role1 TO b_admin CONTAINER=CURRENT;
どれが本当ですか？ （3つ選択してください。）
A. C ## ADMINは、HR_PDBの任意のテーブルを作成および選択できます。
B. B_ADMINは、HR_PDBでのみ任意のテーブルを作成および選択できます。
C. C ## ADMINは、任意のテーブルを作成および選択し、ルートコンテナー内のユーザーのみにC ## ROLE1ロールを付与できます。
D. PDBのc ## role1にローカルロールを付与できます。
E. B_ADMINは、ルートコンテナとHR_PDBの両方で任意のテーブルを作成および選択できます。
F. ロールc ## role1は、各PDBで常に同じ特権を持ちます。
Answer: A,D,F

NEW QUESTION: 4
Refer to the exhibit.

After configuring the routes, the network engineer executes the show ip route command. What is the expected results?
A. Gateway of test resort is 10.0.1.1 to network 0.0.0.0 10.0.0.0/24 is subnetted 1 subnet C 10.0.1.0 is directly connected FastEthernet0/1 S*0.0.0.0/0 [1/0] via 10.0.1.1
B. Gateway of last report is not set
C. Gateway of last resort is 10 0.2 1 to network 0.0.0.0 10 0.0 0/24 is subnetted, 1 subnet C 10.0.2.0 is directly connected, FastEthernet0/0 S* 0.0.0 0/0 [1/0] via 10.0.2.1
D. Gateway of last resort is 10.0.2.1 to network 0.0.0.0 10.0.0.0/24 is subnetted, 2 subnets C 10.0.2.0 is directly connected, FastEthernet0/0 10.0.1.0 is directly connected, FastEthernet0/1 S*0.0.0.0/0 [1/0] via 10.0.2.1(1/0] via 10.0.1.1
Answer: B