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NEW QUESTION: 1
You need to create and configure an Azure Storage account named az400lod11566895stor in a resource group named RG1lod11566895 to store the boot diagnostics for a virtual machine named VM1.
To complete this task, sign in to the Microsoft Azure portal.
Answer:
Explanation:
See solution below.
Explanation
Step 1: To create a general-purpose v2 storage account in the Azure portal, follow these steps:
* On the Azure portal menu, select All services. In the list of resources, type Storage Accounts. As you begin typing, the list filters based on your input. Select Storage Accounts.
* On the Storage Accounts window that appears, choose Add.
* Select the subscription in which to create the storage account.
* Under the Resource group field, select RG1lod11566895
* Next, enter a name for your storage account named: az400lod11566895stor
* Select Create.
Step 2: Enable boot diagnostics on existing virtual machine
To enable Boot diagnostics on an existing virtual machine, follow these steps:
1. Sign in to the Azure portal, and then select the virtual machine VM1.
2. In the Support + troubleshooting section, select Boot diagnostics, then select the Settings tab.
3. In Boot diagnostics settings, change the status to On, and from the Storage account drop-down list, select the storage account az400lod11566895stor.
4. Save the change.

You must restart the virtual machine for the change to take effect.
Reference:
https://docs.microsoft.com/en-us/azure/storage/common/storage-account-create
https://docs.microsoft.com/en-us/azure/virtual-machines/troubleshooting/boot-diagnostics

NEW QUESTION: 2
ステートレスだがCPUとメモリを大量に消費するWeb層がVPC内のcc2 8xlarge EC2インスタンスで実行されているWebスタイルのアプリケーションがあります。
ビジネスで定義されているようにSLA内でリクエストを返すときに問題が発生しているインスタンスアプリケーションはDynamoDBテーブルでその状態を維持しますが、データ層は正しくプロビジョニングされ、レスポンスは一貫して高速です。
SLAを満たしていないアプリケーションの応答の問題をどのように解決するのが最善ですか。
A. 別のcc2 8xlargeアプリケーションインスタンスを追加し、両方をElastic Load Balancerの後ろに置きます
B. スケールアウトリードレプリカ構成でデータベースをDynamoDBからRDS MySQLに移動します
C. cc 2 8倍をDynamoDBテーブルと同じアベイラビリティーゾーンに移動します。
D. より迅速なアクセスのためにElastiCacheにデータベースの応答をキャッシュする
Answer: A
Explanation:
DynamoDB is automatically available across three facilities in an AWS Region. So moving in to a same AZ is not possible / necessary.
In this case the DB layer is not the issue, the EC2 8xlarge is the issue; so add an other one with a ELB in-frond of it.
See also: https://aws.amazon.com/dynamodb/faqs/

NEW QUESTION: 3
You have a Hyper-V host named Server1 that runs Windows Server 2012 R2.
Server1 hosts a virtual machine named VM1 that runs Windows Server 2012 R2.
VM1 has several snapshots.
You need to modify the snapshot file location of VM1.
What should you do?
A. PauseVM1, and then modify the settings of VM1.
B. Right-click VM1, and then click Move.
C. Right-click VM1, and then click Export.
D. Delete the existing snapshots, and then modify the settings of VM1.
Answer: D
Explanation:
Explanation/Reference:
Explanation:
You will need to navigate to the Hyper-V Management snap-in (C:\ProgramData\Microsoft\Windows\Hyper- V) and from there access the Snapshot file Location tab where you can change the settings for the VM1 snapshot file location. However, since there are already several snapshots in existence, you will need to delete them first because you will not be able to change the location of the snapshot file while there is an existing snapshot.
You need to modify the snapshot file location of VM1.

NEW QUESTION: 4
Examine the structure of the EMPLOYEEStable.

There is a parent/child relationship between EMPLOYEE_IDand MANAGER_ID.
You want to display the last names and manager IDs of employees who work for the same manager as the employee whose EMPLOYEE_IDis 123.
Which query provides the correct output?
A. SELECT m.last_name, e.manager_id
FROM employees e LEFT OUTER JOIN employees m
on (e.manager_id = m.manager_id)
WHERE e.employee_id = 123;
B. SELECT e.last_name, m.manager_id
FROM employees e RIGHT OUTER JOIN employees m
on (e.manager_id = m.employee_id)
AND e.employee_id = 123;
C. SELECT e.last_name, m.manager_id
FROM employees e LEFT OUTER JOIN employees m
on (e.employee_id = m.manager_id)
WHERE e.employee_id = 123;
D. SELECT e.last_name, e.manager_id
FROM employees e RIGHT OUTER JOIN employees m
on (e.employee_id = m.employee_id)
WHERE e.employee_id = 123;
Answer: A