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NEW QUESTION: 1



A. Option D
B. Option B
C. Option C
D. Option A
Answer: C
Explanation:
From the routing table we learn that network 192.168.10.0/30 is learned via 2 equal-cost paths
(192.168.10.9 &192.168.10.5) -> traffic to this network will be load-balancing.

NEW QUESTION: 2
ネットワーク10.10.15.0 / 24上のホストからのSSHトラフィックをブロックするために入力できるコマンドはどれですか。
A. access-list 142拒否TCP 10.10.15.0 0.0.0.255任意の式23
B. access-list 142拒否TCP 10.10.15.0 0.0.0.255式21
C. access-list 142拒否TCP 10.10.15.0 0.0.0.255任意の式22
D. access-list 142拒否tcp any 10.10.15.0 0.0.0.0 any eq 22
Answer: C

NEW QUESTION: 3
セキュリティ管理者は、サードパーティの認証局が侵害されたという通知を受け取り、新しい証明書を発行する必要があります。新しい証明書を受け取るために管理者が送信する必要があるのは次のうちどれですか？
A. OSCP
B. CA
C. CRL
D. PFX
E. CSR
Answer: E

NEW QUESTION: 4
View the Exhibit and examine the description for the CUSTOMERS table.

You want to update the CUST_INCOME_LEVEL and CUST_CREDIT_LIMIT columns for the customer with the CUST_ID 2360. You want the value for the CUST_INCOME_LEVEL to have the same value as that of the customer with the CUST_ID 2560 and the CUST_CREDIT_LIMIT to have the same value as that of the customer with CUST_ID 2566.
Which UPDATE statement will accomplish the task?
A. UPDATE customers SET cust_income_level = (SELECT cust_income_level FROM customers WHERE cust_id = 2560), cust_credit_limit = (SELECT cust_credit_limit FROM customers WHERE cust_id = 2566) WHERE cust_id=2360;
B. UPDATE customers SET (cust_income_level,cust_credit_limit) = (SELECT cust_income_level, cust_credit_limit FROM customers WHERE cust_id=2560 AND cust_id=2566) WHERE cust_id=2360;
C. UPDATE customers SET (cust_income_level,cust_credit_limit) = (SELECT cust_income_level, cust_credit_limit
FROM customers
WHERE cust_id IN(2560, 2566)
WHERE cust_id=2360;
D. UPDATE customers SET (cust_income_level,cust_credit_limit) = (SELECT cust_income_level, cust_credit_limit FROM customers WHERE cust_id=2560 OR cust_id=2566) WHERE cust_id=2360;
Answer: A
Explanation:
Updating Two Columns with a Subquery
You can update multiple columns in the SET clause of an UPDATE statement by writing
multiple subqueries. The syntax is as follows:
UPDATE table
SET column =
(SELECT column
FROM table
WHERE condition)
[ ,
column =
(SELECT column
FROM table
WHERE condition)]
[WHERE condition ] ;