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NEW QUESTION: 1
CORRECT TEXT
What is the result, if any, of executing the following code?
DCL A BIT(1) INIT('0'B);
DCL B BIT(1) INIT('0'B);
DCL C BIT(1) lNlT('1'B);
A = B ! C;
A. There is no result, because the syntax is wrong.
B. The value of A is'1'
C. The value of A is '0'B
D. The value of A is unpredictable.
Answer: B

NEW QUESTION: 2
View the Exhibit.

You administer the network shown above. You want to summarize the networks connected to RouterA so that a single route is inserted into RouterB's routing table.
Which of the following is the smallest summarization for the three networks?
A. 172.16.1.0/22
B. 172.16.1.0/25
C. 172.16.1.0/23E.
D. 172.16.1.0/16
E. 172.16.1.0/18
Answer: A
Explanation:
Explanation/Reference:
Section: Addressing and Routing Protocols in an Existing Network Explanation Explanation:
The smallest summarization for the three networks connected to RouterA is 172.16.1.0/22, which is equivalent to a network address of 172.16.1.0 and a subnet mask of 255.255.252.0. In this scenario, the Class B 172.16.0.0/16 network has been divided into 256 /24 subnets. Three of the first four subnets in the Class B range have been assigned to network interfaces on RouterA: 172.16.0.0/24, 172.16.1.0/24, and
172.16.3.0/24. Absent from the network assignments is the 172.16.2.0/24 subnet. However, there is no way to summarize the address range without including the 172.16.2.0/24 subnet. Therefore, the smallest summarization you can create would summarize four subnets into a single /22 subnet.
A /22 subnet creates 64 subnetworks capable of supporting 1,022 assignable host IP addresses each. The assignable address range of the 172.16.0.0/22 subnet begins with 172.16.0.1 and ends with 172.16.3.255.
This range includes all possible assignable IP addresses in the /24 subnets that are directly connected to RouterA. It also includes all possible assignable IP addresses in the 172.16.2.0/24 subnet.
Subnetting a contiguous address range in structured, hierarchical fashion enables routers to maintain smaller routing tables and eases administrative burden when troubleshooting. Conversely, a discontiguous IP version 4 (IPv4) addressing scheme can cause routing tables to bloat because the subnets cannot be summarized. Summarization minimizes the size of routing tables and advertisements and reduces a router's processor and memory requirements.
Summarizing the three /24 networks with a /16 subnet would create too large of a summarization, because the /16 subnet contains the entire Class B range of 172.16.0.0 IP addresses. The first assignable IP address in the 172.16.0.0/16 range is 172.16.0.1. The last assignable IP address is 172.16.255.255. The range would therefore summarize 256 /24 subnets, not four.
Summarizing the three /24 networks with a /18 subnet would create too large of a summarization. A /18 subnet creates four possible subnets containing 16,382 assignable host IP addresses each. The first assignable IP address in the 172.16.0.0/18 range is 172.16.0.1. The last assignable IP address is
172.16.63.255. The range would therefore summarize 64 /24 subnets, not four.
Summarizing the three /24 networks with a /23 subnet would create too small of a summarization. A /23 subnet creates 128 possible subnets containing 510 assignable host IP addresses each. The first assignable IP address in the 172.16.0.0/23 range is 172.16.0.1. The last assignable IP address is
172.16.1.255. This range would therefore exclude the 172.16.3.0/24 subnet connected to RouterA.
Summarizing the three /24 networks with a /25 subnet would not work, because a /25 subnet divides the
172.16.0.0/24 subnet instead of summarizing. A /25 subnet creates 512 possible subnets containing 126 assignable host IP addresses each. The first assignable IP address in the 172.16.0.0/25 range is
172.16.0.1. The last assignable IP address is 172.16.0.127. This subnet would therefore contain only half of one the subnets that is directly connected to RouterA.
Reference:
CCDA 200-310 Official Cert Guide, Chapter 8, Plan for a Hierarchical IP Address Network, pp. 311-312 Cisco: IP Addressing and Subnetting for New Users

NEW QUESTION: 3
Where is the default run-state found?
A. /etc/inittab
B. /etc/rc
C. /sbin/bcheckrc
D. defined by the user at boot time
E. /etc/rc.config.d
Answer: A

NEW QUESTION: 4
A client with asthma develops respiratory acidosis. Based on this diagnosis, what should the nurse expect the client's serum potassium level to be?
A. elevated
B. low
C. unrelated to the pH
D. normal
Answer: A
Explanation:
Hyperkalemia occurs in a state of acidosis because potassium moves from injured cells into the bloodstream.
Physiological Adaptation