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NEW QUESTION: 1
In a VPRN, what type of logical topology is required for the BGP sessions configured in the provider core?

A. Full mesh between all CE, PE and P devices
B. Full mesh of PE devices
C. Full mesh between PE and P devices
D. Full mesh between PE and CE devices
E. Full mesh of P devices
Answer: B

NEW QUESTION: 2
Your network contains an Active Directory domain named contoso.com. The domain contains several domain controllers. The domain controllers run either Windows Server 2012 or Windows Server 2008 R2.
The domain functional level is Windows Server 2008 R2. The forest functional level is Windows Server
2008.
The corporate compliance policy states that all items deleted from Active Directory must be recoverable from a Recycle Bin.
You need to recommend changes to the current environment to meet the compliance policy.
Which changes should you recommend? (Each correct answer presents part of the solution. Choose all that apply.)
A. Run the Enable-ADOptionalFeature cmdlet.
B. Run the New-ADObject cmdlet.
C. Run the Set-Server cmdlet
D. Raise the forest functional level to Windows Server 2008 R2.
E. Raise the domain functional level to Windows Server 2012.
Answer: A,D
Explanation:
You can enable Active Directory Recycle Bin only if the forest functional level of your environment is set to Windows Server 2008 R2.
B: Enabling Active Directory Recycle Bin
After the forest functional level of your environment is set to Windows Server 2008 R2, you can enable Active Directory Recycle Bin by using the following methods:
/ Enable-ADOptionalFeature Active Directory module cmdlet (This is the recommended method.)
/ Ldp.exe
Note: By default, Active Directory Recycle Bin in Windows Server 2008 R2 is disabled.
Reference: Enable Active Directory Recycle Bin

NEW QUESTION: 3
When cost variance is negative and schedule variance is positive, the project is:
A. over budget and ahead of schedule.
B. complete; all planned values have been earned.
C. on schedule.
D. under budget and behind schedule.
Answer: A

NEW QUESTION: 4



A. IntFunction funRef = e -> e + 10;
Integer result = funRef.apply (10);
B. ToIntFunction<Integer> funRef = e -> e + 10;
int result = funRef.applyAsInt (value);
C. Function<Integer> funRef = e -> e + 10;
Integer result = funRef.apply(value);
D. ToIntFunction funRef = e -> e + 10;
int result = funRef.apply (value);
Answer: C