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NEW QUESTION: 1
Which layer of the OSI model is associated with Token Ring Media Access Control?
A. routing
B. data link
C. datagram
D. session
E. transmission
F. network
G. transport
Answer: B
Explanation:
"Token ring local area network (LAN) technology was a protocol which resided at the data link layer (DLL) of the OSI model." http://en.wikipedia.org/wiki/Token_ring

NEW QUESTION: 2
The security manager is in the process of writing a business case to replace a legacy secure web gateway so as to meet an availability requirement of 99.9% service availability.
According to the vendor, the newly acquired firewall has been rated with an MTBF of 10,000 hours and has an MTTR of 2 hours. This equates to 1.75 hours per year of downtime. Based on this, which of the following is the MOST accurate statement?
A. The firewall will meet the availability requirement because availability will be 99.993%.
B. The firewall will not meet the availability requirement because availability will be 99.2%.
C. The firewall will meet the availability requirement because availability will be 99.98%.
D. The firewall will not meet the availability requirement because availability will be 85%.
Answer: C

NEW QUESTION: 3
sys管理者が以下のポリシーを作成し、aws.jpgという名前のS3オブジェクトに適用しました。 aws.jpgはcloudacademyという名前のバケット内にあります。このポリシーは何を定義していますか？

A. バケットcloudacademyのすべてのオブジェクトを公開します
B. aws.jpgオブジェクトをパブリックとして
C. オブジェクトレベルでポリシーを定義することはできません
D. バケットcloudacademyを公開します
Answer: C
Explanation:
説明
システム管理者は、S3オブジェクトまたはバケットへのアクセス許可を任意のユーザーに付与したり、バケットポリシーとユーザーポリシーを使用してオブジェクトをパブリックにしたりできます。どちらもJSONベースのアクセスポリシー言語を使用します。一般に、ユーザーがバケットにACLを定義している場合、バケット内のオブジェクトはそれを継承せず、その逆も同様です。バケットポリシーはバケットレベルで定義でき、単一のポリシーをそのバケットに適用してオブジェクトとバケットをパブリックにすることができます。オブジェクトレベルでは適用できません。

NEW QUESTION: 4
Refer to the exhibit.

Which command is simplest to configure routing between the regional office network 10.89.0.0/20 and the corporate network?
A. router1(config)#ip route 10.89.0.0 255.255.240.0 10.89.16.1
B. router2(config)#ip route 10.89.3.0 255.255.0.0 10.89.16.2
C. router2(config)#ip route 0.0.0.0 0.0.0.0 10.89.16.1
D. router1(config)#ip route 10.89.0.0 255.255.240.0 10.89.16.2
Answer: C