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When choosing a product, you will be entangled.

NEW QUESTION: 1

A. Option B
B. Option D
C. Option C
D. Option A
Answer: B

NEW QUESTION: 2
How can a majority of IBM Tivoli Endpoint Manager Console issues be fixed?
A. clear the Console cache and restart the Console application
B. request a new masthead and restart the Console application
C. reboot the system running the Console application
D. run the BES Console and select Clear Console Cache task
Answer: A

NEW QUESTION: 3
Which TRANLOCATIONS parameter option is required for supporting bidirectional replication when using MySQL as a source database?
A. FILTERTABLE
B. EXCLUDETAG
C. EXCLUDETRANS
D. EXCLUDEUSER
Answer: A

NEW QUESTION: 4
学生の年半ば成績を記録するためにStudentCode、SubjectCodeおよび成績カラムを持っているテーブルを作成します。 テーブルには様々な主題のために50人の学生によって得られたマークがあります。あなたは、マークと一緒に、各被験者の最高点を獲得した学生を取得する必要があります。どのTransact-SQLクエリを使うべきでしょうか。
A. SELECT StudentCode as Code, RANK() OVER(ORDER BY AVG(Marks) DESC) AS Value FROM StudentMarks GROUP BY StudentCode
B. SELECT StudentCode as Code, DENSE_RANK() OVER(ORDER BY AVG(Marks) DESC) AS Value FROM StudentMarks GROUP BY StudentCode
C. SELECT Id, Name, Marks, DENSE_RANK() OVER(ORDER BY Marks DESC) AS Rank FROM StudentMarks
D. SELECT StudentCode AS Code, Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANK() OVER(PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
E. SELECT StudentCode AS Code, Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANXO OVER(PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
F. SELECT StudentCode AS Code, Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
G. SELECT StudentCode AS Code, Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
H. SELECT StudentCode as Code, NTILE(2) OVER(ORDER BY AVG(Marks) DESC) AS Value FROM StudentMarks GROUP BY StudentCode
Answer: G