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NEW QUESTION: 1
Given the host IP address of 192.168.100.60 and a network mask of 255.255.255.224 (or /27), which address represents the correct network address for the referenced host?
A. 192.168.100.32
B. 192.168.100.16
C. 192.168.100.48
D. 192.168.100.0
Answer: A
Explanation:
Explanation
Network is a class C network: 192.168.100.32/27
Binary: 11000000.10101000.01100100.001 00000
References:
http://jodies.de/ipcalc?host=192.168.100.60
&mask1=27&mask2

NEW QUESTION: 2
Documented work authorization provide:
A. All of the other alternatives apply
B. a means of effective internal coordination of the project's activities.
C. Both 1) a means of effective internal coordination of the project's activities, and 2) an audit trail of all work authorized from project initiation to completion.
D. an audit trail of all work authorized from project initiation to completion.
E. a means for communication of work activity between the project manager and the performing activities.
Answer: A

NEW QUESTION: 3
How can a user list the IAM Role configured as a part of the launch config?
A. as-describe-launch-configs -iam-profile
B. as-describe-launch-configs -role
C. as-describe-launch-configs -show-long
D. as-describe-launch-configs -iam-role
Answer: C
Explanation:
Explanation
As-describe-launch-configs describes all the launch config parameters created by the AWS account in the specified region. Generally, it returns values, such as Launch Config name, Instance Type and AMI ID. If the user wants additional parameters, such as the IAM Profile used in the config, he has to run command:
as-describe-launch-configs --show-long

NEW QUESTION: 4
View the exhibit and examine the structure of the EMPLOYEEStable.

You want to display all employees and their managers having 100 as the MANAGER_ID. You want the output in two columns: the first column would have the LAST_NAMEof the managers and the second column would have LAST_NAMEof the employees.
Which SQL statement would you execute?
SELECT m.last_name "Manager", e.last_name "Employee"
A. FROM employees m JOIN employees e
ON e.employee_id = m.manager_id
WHERE m.manager_id = 100;
SELECT m.last_name "Manager", e.last_name "Employee"
B. FROM employees m JOIN employees e
ON m.employee_id = e.manager_id
WHERE e.manager_id = 100;
SELECT m.last_name "Manager", e.last_name "Employee"
C. FROM employees m JOIN employees e
WHERE m.employee_id = e.manager_id AND e.manager_id = 100
D. FROM employees m JOIN employees e
ON m.employee_id = e.manager_id
WHERE m.manager_id = 100;
SELECT m.last_name "Manager", e.last_name "Employee"
Answer: B