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NEW QUESTION: 1
How can a protocol analyzer be used?
A. to distribute messages according to the addressing protocol they use
B. to measure the bandwidth required for different types of transactions
C. to prevent virus infections in the network software
D. to analyze errors in the protocol syntax used in a failed message
Answer: B

NEW QUESTION: 2
What is the function of an EIGRP sequence TLV packet?
A. to list the peers that should not listen to the next multicast packet during the reliable multicast process
B. to acknowledge a set of sequence numbers during the startup update process
C. to define the initial sequence number when bringing up a new peer
D. to list the peers that should listen to the next multicast packet during the reliable multicast process
Answer: A
Explanation:
EIGRP sends updates and other information between routers using multicast packets to 224.0.0.10. For example in
the topology below, R1 made a change in the topology and it needs to send updates to R2 & R3. It sends multicast
packets to EIGRP multicast address 224.0.0.10. Both R2 & R3 can receive the updates and acknowledge back to R1
using unicast. Simple, right?
But what if R1 sends out updates, only R2 replies but R3 never does? In the case a router sends out a multicast packet
that must be reliable delivered (like in this case), an EIGRP process will wait until the RTO (retransmission timeout)
period has passed before beginning a recovery action. This period is calculated from the SRTT (smooth round-trip
ti me). After R1 sends out updates it will wait for this period to expire. Then it makes a list of all the neighbors from
which it did not receive an Acknowledgement (ACK). Next it sends out a packet telling these routers stop listening to
multicast until they are been notified that it is safe again. Finally the router will begin sending unicast packets with the
information to the routers that didn't answer, continuing until they are caught up. In our example the process will be
like this:
1. R1 sends out updates to 224.0.0.10
2. R2 responds but R3 does not
3. R1 waits for the RTO period to expire
4. R1 then sends out an unreliable-multicast packet, called a sequence TLV (Type-Length-Value) packet, which tells R3
not to listen to multicast packets any more
5. R1 continues sending any other muticast traffic it has and delivering all traffic, using unicast to R3, until it
acknowledges all the packets
6. Once R3 has caught up, R1 will send another sequence TLV, telling R3 to begin listening to multicast again.
The sequence TLV packet contains a list of the nodes that should not listen to multicast packets while the recovery
takes place. But notice that the TLV packet in step 6 does not contain any nodes in the list.
Note. In the case R3 still does not reply in step 4, R1 will attempt to retransmit the unicast 16 times or continue to
retransmit until the hold time for the neighbor in question expires. After this time, R1 will declare a retransmission
limit exceeded error and will reset the neighbor.
(Reference: EIGRP for IP: Basic Operation and Configuration)

NEW QUESTION: 3
Which CLI command is used to display output one page at a time?
A. user@router> show interfaces
B. user@router> show interfaces | display
C. user@router> show interfaces | trim
D. user@router> show interfaces | no-more
Answer: A

NEW QUESTION: 4
You are developing a Windows Communication Foundation (WCF) service that contains the following operation contract.
[OperationContract]
CustomerNames GetCustomerNames();
The operation returns customer names.
You need to develop a definition for the operation contract that produces XML with the following structure.

Which code segment should you use?
A. [MessageContract(WrapperName = "")]
public class CustomerNames
{
B. [MessageBodyMember]
public string[] Names;
}
C. [DataMember(IsRequired = false)]
public string[] Names;
}
D. [DataContract]
public class CustomerNames
{
E. [MessageContract(IsWrapped = false)]
public class CustomerNames
{
[MessageBodyMember]
public string[] Names;
}
F. [DataContract]
public class CustomerNames
{
[DataMember]
public string[] Names;
}
Answer: E