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NEW QUESTION: 1
Hyperledger is a membership based distributed ledger platform. What determine the level of permissions required to transact for members?
A. Authentication Services
B. Validator Services
C. Identity Management
D. Audit Services
Answer: B
Explanation:
Explanation
Hyperledger is a private validator network protocol. All the entities in a network must register with membership services to obtain an identity with access and transaction authority on the network. Validators determine the level of permissions required to transact. The network setup also defines the network as permissive, allowing the ease of access. It supports for rapid and high adoption for a more controlled and restrictive environment.

NEW QUESTION: 2
What are the differences between a private web browser window and a regular web browser window? (Choose three.)
A. Private web browser windows do not support logins into websites.
B. Private web browser windows do not store cookies persistently.
C. Private web browser windows do not allow printing or storing websites.
D. Private web browser windows do not send regular stored cookies.
E. Private web browser windows do not keep records in the browser history.
Answer: B,D,E

NEW QUESTION: 3
Telnet protocol uses the port number is
A. 0
B. 1
C. 2
D. 3
Answer: D

NEW QUESTION: 4
You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year marks for students. The table has marks obtained by 50 students for various subjects.
You need to ensure that the following requirements are met:
- Students must be ranked based on their average marks. - If one or more students have the same average, the same rank must be given to these students. - Consecutive ranks must be skipped when the same rank is assigned.
Which Transact-SQL query should you use?
A. SELECT StudentCode AS Code,Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks DESC) AS Rank FROM StudentMarks) tmp WHERE Rank = 1
B. SELECT StudentCode AS Code,Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANK() OVER(PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank FROM StudentMarks) tmp WHERE Rank = 1
C. SELECT StudentCode as Code, NTILE(2) OVER(ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks GROUP BY StudentCode
D. SELECT StudentCode as Code, DENSE_RANK() OVER(ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks GROUP BY StudentCode
E. SELECT StudentCode AS Code,Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank FROM StudentMarks) tmp WHERE Rank = 1
F. SELECT StudentCode as Code, RANK() OVER(ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks GROUP BY StudentCode
G. SELECT StudentCode AS Code,Marks AS Value FROM ( SELECT StudentCode, Marks AS Marks, RANXO OVER(PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank FROM StudentMarks) tmp WHERE Rank = 1
H. SELECT Id, Name, Marks, DENSE_RANK() OVER(ORDER BY Marks DESC) AS Rank FROM StudentMarks
Answer: F
Explanation:
Reference: http://msdn.microsoft.com/en-us/library/ms189798.aspx