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NEW QUESTION: 1
Given that data.txt and alldata.txt are accessible, and the code fragment:

What is required at line n1 to enable the code to overwrite alldata.txt with data.txt?
A. br.close();
B. br.flush();
C. bw.writeln();
D. bw.flush();
Answer: D

NEW QUESTION: 2
ユーザーがEC2インスタンスを起動し、Apache Webサーバーを使用してWebサイトをインストールしました。 Webサーバーは実行されていますが、ユーザーはインターネットからWebサイトにアクセスできません。この失敗の考えられる理由は何ですか？
A. Apache Webサイトはインターネットからアクセスできません。
B. インスタンスのセキュリティグループが正しく設定されていません。
C. インスタンスはエラスティックIPで構成されていません。
D. インスタンスは適切なキーペアで設定されていません。
Answer: B
Explanation:
Amazon Web Servicesでは、ユーザーがApacheでインスタンスを設定したとき、ユーザーは、セキュリティグループのポートがApache configで設定されているとおりに開かれていることを確認する必要があります。例えば。
Apacheがポート80で実行されている場合、ユーザーはセキュリティグループのポート80を開く必要があります。
http://docs.aws.amazon.com/AWSEC2/latest/UserGuide/using-network-security.html

NEW QUESTION: 3
Where can an administrator create a new built-in exception on the ProxySG?
A. In the Visual Policy Manager
B. In the Management Console
C. In the CU
D. An administrator is unable to do this
Answer: D

NEW QUESTION: 4
You are a database developer of a Microsoft SQL Server 2016 database. You are designing a table that will store Customer data from different sources. The table will include a column that contains the CustomerID from the source system and a column that contains the SourceID. A sample of this data is as shown in the following table. You need to ensure that the table has no duplicate CustomerID within a SourceID. You also need to ensure that the data in the table is in the order of SourceID and then CustomerID.
Which Transact- SQL statement should you use?
A. CREATE TABLE Customer
(SourceID int NOT NULL,
CustomerID int NOT NULL PRIMARY KEY CLUSTERED,
CustomerName varchar(255) NOT NULL);
B. CREATE TABLE Customer
(SourceID int NOT NULL PRIMARY KEY CLUSTERED,
CustomerID int NOT NULL UNIQUE,
CustomerName varchar(255) NOT NULL);
C. CREATE TABLE Customer
(SourceID int NOT NULL,
CustomerID int NOT NULL,
CustomerName varchar(255) NOT NULL,
CONSTRAINT PK_Customer PRIMARY KEY CLUSTERED
(SourceID, CustomerID));
D. CREATE TABLE Customer
(SourceID int NOT NULL IDENTITY,
CustomerID int NOT NULL IDENTITY,
CustomerName varchar(255) NOT NULL);
Answer: C