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NEW QUESTION: 1
Which of the following statements are true for Condition Evaluation for Internal Communication?
There are 2 correct answers to this question.
A. To increase the amount of messages, you can define that a message is raised only for example, when the source business object has a specific status.
B. For each business object identified as relevant for the subsequent service integration process, the system can evaluate a start condition, change condition and a cancel condition.
C. Condition evaluation is used to determine when a business object needs to send a message to the target business object, for example, a message to create or change a business object instance.
D. By default, the system does not sends a message every time a business object is change or deleted.
Answer: B,C
NEW QUESTION: 2
A. Option B
B. Option E
C. Option C
D. Option A
E. Option D
Answer: B,D,E
NEW QUESTION: 3
As a database architect you are tasked with configuring a high concurrency, production OLTP application to connect to an Autonomous Transaction Processing database with a requirement to have some reporting queries run in parallel mode.
Which connection service is appropriate for such a workload?
A. HIGH
B. TPURGENT
C. TP
D. MEDIUM
Answer: B
NEW QUESTION: 4
What happens when you attempt to compile and run the following code?
#include <iostream>
#include <algorithm>
#include <deque>
#include <vector>
using namespace std;
bool identical(int a, int b) {
return b == 2*a?true:false;
}
int main() {
int t[] = {1,2,3,2,3,5,1,2,7,3,2,1,10, 4,4,5};
int u[] = {2,4,6,4,6,10,2,4,14,6,4,2,20,8,8,5};
vector<int> v1(t, t + 15);
deque<int> d1(u, u + 15);
pair<deque<int>::iterator, vector<int>::iterator > result;
result = mismatch(d1.begin(), d1.end(), v1.begin(), identical); //Line I if (result.first == d1.end() && result.second == v1.end()) {//Line II
cout<<"Identical\n";
} else {
cout<<"Not identical\n";
}
return 0;
}
Program outputs:
A. compilation error at line marked II
B. compilation error at line marked I
C. Not identical
D. Identical
Answer: C
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