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NEW QUESTION: 1
If X is a positive integer and (405) 4 is a multiple of 3X, what is the largest possible value of X?
A. 26.
B. 12.
C. 0
D. 16.
E. 5.
Answer: D
Explanation:
Explanation/Reference:
Explanation:
Find the factors of (405) 4 and see what the largest value of X can be.
405 = 81 x 5 = 9 x 9 x 5 = 3 x 3 x 3 x 3 x 5 -ꢀ(405) 4 = (3 x 3 x 3 x 3 x 5) 4 = 316 x 54.
The largest possible value of 3X that is still a factor of (405) 4 is the largest possible value of X and that is
316. X = 16. The correct answer is C.

NEW QUESTION: 2
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B. Float
C. String
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NEW QUESTION: 3
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D. 人的資源管理を計画します。
Answer: A