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NEW QUESTION: 1
You are the Microsoft Lync Online administrator for your company. A customer has reported an issue when signing in to the company's Lync Online Service. When the customer attempts to sign in, the following error message is returned:
"The server is temporarily unavailable".
The server is up, and other customers are connected to it.
What is likely causing the connection issue?
A. The user has entered the wrong user name
B. DNS is configured incorrectly
C. The user does not have a Lync license
D. The user has the incorrect Lync version
Answer: C
Explanation:
Explanation/Reference:
This issue occurs for one of the following reasons:
Cause 1: You are not entitled for Lync Online.
Cause 2: You lack connectivity to the Lync Online service.
Cause 3: You are running a 64-bit Windows operating system.
Reference: "Cannot sign in because the server is temporarily unavailable" error when you try to sign in to Lync Online in Office 365 dedicated
https://support.microsoft.com/en-us/kb/2619522

NEW QUESTION: 2
HOTSPOT
You discover that one of the Client Access servers in the New York office does not trust the standalone CA.
You need to ensure that all of the users who have Windows Phone devices can connect successfully to their mailbox.
In which node should you install the root CA certificate?
To answer, select the appropriate node in the answer area.

Answer:
Explanation:

NEW QUESTION: 3
Sie sind Datenbankentwickler für eine Anwendung, die auf einem Microsoft SQL Server 2014-Server gehostet wird. Die Datenbank enthält zwei Tabellen mit folgenden Definitionen:

Weltweite Kunden bestellen aus mehreren Ländern. Sie müssen das Land anzeigen, aus dem jeder Kunde die meisten Bestellungen aufgegeben hat.
Welche Transact-SQL-Abfrage verwenden Sie?
A. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer CINNER JOIN (SELECT CustomerID, Versandland, RANK () OVER (PARTITION NACH CustomerIDORDER NACH COUNT (OrderAmount) DESC) AS RnkFROM OrdersGROUP BY CustomerID, Versandland) AS oON c.CustomerID = o.CustomerIDWHERE o.Rnk = 1
B. Wählen Sie c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer CINNER aus OrderAmount DESC
C. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer CINNER JOIN (SELECT customerID, ShippingCountry, RANK () OVER (PARTITION NACH CustomerIDORDER NACH OrderAmount DESC) AS RNKFROM OrdersGROUP NACH CustomerID, ShippingCountry) ASOON CustomerID = o.CustomerIDWHERE o.Rnk = 1
D. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM (SELECT c.CustomerID, c.CustomerName, o.ShippingCountry, RANK () OVER (PARTITION BY CustomerIDORDER BY COUNT (o.OrderAmount) ASC) AS RnkFROM Kunden-CINNER JOIN Bestellungen oON c.CustomerID = o.CustomerIDGROUP BY c.CustomerID, c.CustomerName, o.ShippingCountry) cs WHERE Rnk = 1
Answer: A
Explanation:
Erläuterung
Verwenden Sie die absteigende Reihenfolge (DESC).
Um nach der Anzahl der Bestellungen zu bestellen, verwenden wir ORDER BY COUNT (OrderAmount).
Schließlich wird ein WHERE-Abschluss benötigt: WHERE o.Rnk = 1

NEW QUESTION: 4
HOTSPOT
HOTSPOT




Answer:
Explanation: