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NEW QUESTION: 1
Refer to the Exhibit.

In the Exhibit, the table shows the values for the input Boolean attributes "A", "B", and "C". It also shows the values for the output attribute "class". Which decision tree is valid for the data?
A. Tree D
B. Tree C
C. Tree A
D. Tree B
Answer: D

NEW QUESTION: 2
Which two methods should be used to add custodians to the Legal Hold module in Symantec eDiscovery Platform 8.0? (Select two.)
A. Import from script
B. Import using Custodian Manager
C. Synchronize Now with Active Directory
D. Add from Custodian Template
E. Perform Custodian Load File Import
Answer: A,C

NEW QUESTION: 3
You are implementing an ASP.NET web application.The application defines the following classes. public class Person {
public String Name{get; set;} publicIList<Address> Addresses{get;set;} }
public class Address
{ public String AddressType{get; set;} public string AddressValue{get;set;}
}
The applicaction must generate XML from personList, wich is a collection of Person instances.The following
XML is an example of the schema than the generated XML must use.
<Persons>
<Person Name="John Doe">
<Address Email="[email protected]"/>
<Address AlternativeEmail="[email protected]"/>
<Address MSNInstanceMessenger="[email protected]"/>
</Person>
.....
</Persons>
You need to generate the XML.
Wich code segment should you use?
A. var XML= new XElement("Persons", from person in personList
Select (new XElement("Persons",
newXElement("Name", person.Name),
from addr in person.Addresses
select new XElement("Address",
newXElement(addr.AddressType,
addr.AddressValue)))));
B. var XML= new XElement("Persons", from person in personList
Select (new XElement("Person",
newXAttribute("Name", person.Name),
from addr in person.Addresses
select new XElement("Address",
newXAttribute(addr.AddressType,
addr.AddressValue)))));
C. var XML= new XAttribute("Persons", from person in personList
Select (new XElement("Persons",
newXAttribute("Name", person.Name),
from addr in person.Addresses
select new XAttribute("Address",
newXAttribute(addr.AddressType,
addr.AddressValue)))));
D. var XML= new XElement("Persons",
from person in personList
Select (new XElement("Persons",
newXAttribute("Name", person.Name))));
Answer: B