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NEW QUESTION: 1
An air-conditioning unit costs $470. On December there was a discount for Christmas of 16%. Six months later, the holiday season was over so the company raised the price of the air-conditioning by 16%. How much will an air-conditioning unit cost in November?
A. $472
B. $458
C. $491
D. $484
E. $470
Answer: B
Explanation:
Explanation/Reference:
Explanation:
Pay attention, when you raise a number by X% and than you reduce X% you don't get the original number again because the second time you took X% off you reduced it from a larger number thus answer A is not the correct one, let's check:
470 x 0.84 = 394.8.
394.8 x 1.16 = approximately $458.
A simpler way to solve this problem is by knowing that the price would be lower than the original price because we increased and decreased the same amount of percentage.

NEW QUESTION: 2
What are the steps necessary to trace SIP messages going through the Avaya Session Border Controller for Enterprise (SBCE)?
A. Login to the EMS using a web browser, then access Device specific settings > Troubleshooting > Tracing, and click on Start traceSBC.
B. Login to the active Avaya Session Border Controller for Enterprise (SBCE) using SSH port 222, issue the sudo sucommand, and then execute the traceSBCcommand.
C. Login to the EMS using port SSH 222, issue the sudo sucommand, and then execute the traceSBC command.
D. Login to the active Avaya Session Border Controller for Enterprise (SBCE) using SSH port 22, issue the su - rootcommand, and then execute the traceSBC command.
Answer: A

NEW QUESTION: 3
Which of the following distribution assumptions will produce the lowest probability of exceeding an extreme value, assuming identical means and variances?
A. a normal mixture distribution
B. a normal distribution
C. t-distribution
D. a distribution with kurtosis = 5
Answer: B
Explanation:
Explanation
An 'extreme value' will be a value that will lie in the tails. We need to determine the distribution that will have the least weight in the tails so that the probability of exceeding this tail value is minimum across the given choices.
The t-distribution, a distribution with kurtosis > 3 and a normal mixture distribution are all distributions with tails fatter than that for a normal distribution. A normal distribution will have the 'thinnest' tails among the choices and therefore the lowest probability of exceeding a given tail event value.
A note about the t-distribution: Leptokurtic distributions (those that have kurtosis>3, ie kurtosis greater than that for a normal distribution) generally appear to have higher peaks on their PDF graphs. The t-distribution is flatter, and actually appears lower than a normal distribution, which may make one think that it has a lower kurtosis and therefore should have thinner tails than a normal distribution. But that is not so, and the "visual" inspection test fails for inferring the kurtosis from just looking a the shape of the distribution. The kurtosis of a t-distribution is given by the formula {3 + 6/(d - 4)}, where d is the degrees of freedom and d > 4. Therefore the kurtosis of a t-distribution is always greater than 3 as "6/(d-4)" will always be a positive number being added to 3. Therefore there is no conflict between a t-distribution having fatter tails than a normal distribution as it has a higher kurtosis, even though it appears 'lower' on a graph when superimposed with a normal distribution.