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NEW QUESTION: 1
로드 밸런서를 사용하는 웹 사이트를 관리합니다. 서버 중 하나가 다른 서버보다 많은 트래픽을 수신하고 있음을 알수 있습니다. 아마도 이것의 원인은 무엇입니까? 정답을 선택하십시오.
A. 고정 세션이 구성되었고 다른 서버에 있는 여러 고급 사용자가 있습니다.
B. Elastic Load Balancer는 서버로드를 기반으로 트래픽을 보냅니다. 하나의 서버는 더 큰 인스턴스여야 합니다.
C. 서버에 더 많은 연결이 있습니다.
D. DNS 대기 시간 라우팅이 설정되어 트래픽을 다른 인스턴스로 전환합니다.
Answer: A
Explanation:
Sticky sessions can keep users on a particular server throughout their session. Latency routing would route to the load balancer, not the instances. Load balancers use a round-robin algorithm to balance.

NEW QUESTION: 2

A. 2001:bad:2345:a:b::cef/128
B. 2001:aaaa: 1234:456c: 1/64
C. 2001:000a:lb2c::/64
D. 2fff:f:f:f::f/64
E. ff02:33ab:l:32::2/128
F. ff02:a:b:c::l/64
Answer: A,B
Explanation:
Explanation
Option B is valid, assuming theres a faulty colon : in the IPv6 Address, just before the last 1, that is:
2001:aaaa:1234:456c::1/64Option F is valid, dispite its odd network mask (128 bits), sometimes used in tunnel links.
Incorrect answer:
Option A is invalid, since it is a Multicast addressOption C seems to be invalid because the 3rd group of characters includes an l (lb2c), but if it is a 1 instead of an l (faulty scan) and the required options are 3 instead of 2, then this address is still valid (2001:000a:1b2c::/64), because the 4th group of characters would be 0000 (remember that we can represent a continuous sequence of zeros by ::).Option D is definitely invalid since it is a reserved address. As states the IANA online :document about the IPv6 Unicast Global Addresses, the range below is reserved, not allocated to any RIR (Regional Internet Registry):
2E00:0000::/7 IANA 1999-07-01 RESERVED
Reference:
http://www.iana.org/assignments/ipv6-unicast-address-assignments/ipv6-unicast-address-assignments.txt

NEW QUESTION: 3
Which of these options best describes a skill level required for desk-side support?
A. Incident Management knowledge
B. Management competency
C. Basic level technical skills
D. High levels of process development knowledge
Answer: A

NEW QUESTION: 4
What is an advantage of HP APM for scale-out compute in the Apollo 8000?
A. Less potential capacity is needed.
B. Fewer components and cables are required.
C. Measurement of interconnect throughput is more accurate.
D. More compute performance is realized.
Answer: B