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NEW QUESTION: 1
What types of testing are particularly important for mobile applications based on the user's expectations?
A. Performance and Security
B. Portability and Usability
C. Usability andPerformance
D. Suitability and Accuracy
Answer: C
Explanation:
Explanation
While all of these are important, the user has particularly high expectations for the usability and performance of a mobile application.

NEW QUESTION: 2
あなたはSASCOM Network Ltd社のネットワークエンジニアとして働いています。ルーターHQでプロバイダーリンクが有効になっているので、HQでIPv6デフォルトルートを設定し、このルートがIPv6 OSPFプロセスでアドバタイズされていることを確認する必要があります。また、別の問題を解決しなければなりません。ルータHQは、ルータBRとIPv6 OSPFネイバー関係を形成していません。
トポロジの詳細
2台のルータHQとBRがシリアルリンクで接続されています。
ルーターHQのプロバイダーEthernetに接続されたインターフェースEthernet0 / 1とRA1に接続されたインターフェースEthernet 0/0は別のルーターRA2に接続されたインターフェースEthernet 0/0を持っています。
IPv6ルーティング詳細
すべてのルーターがプロセスID番号100でIPv6 OSPFルーティングを実行しています。OSPFエリアについては、トポロジー図を参照してください。Loopback 0 IPv4アドレスは、各ルーターのOSPFルーターIDです。構成要件
*デフォルトゲートウェイが2001：DB8：B：B1B2 :: 1のルータHQでIPv6デフォルトルートを設定します。
*HQでデフォルトルートを設定した後、pingテストプロバイダーテストIPv6アドレス2001：DB8：0：1111：1。
*デフォルトルートがルーターHQのIPv6 OSPFでアドバタイズされていることを確認してくださいこのデフォルトルートは、HQのルーティングテーブルにデフォルトルートがある場合にのみアドバタイズされる必要があります。
*ルータHQはBRとIPv6 OSPFネイバーを形成していません。この問題を解決し、解決しなければなりません。特記事項：最大ポイント数を得るには、必要な設定を完了し、ルータBRでのIPv6 OSPFネイバー問題を修正する必要があります。 IPv6 OSPFプロセスIDを変更しないでください。

A. See the full configuration and steps below.
1-configure default route on router HQ : ipv6 unicast-routing
ipv6 route ::/0 2001:DB8:B:B1B2::1
2-advertise this route under ospfv3
Ipv6 router ospf 100
Default-information originate
3-fix adjacency problem if a area mismatches
We need to enter in s1/0
Ipv6 ospf 100 area 0
B. See the full configuration and steps below.
1-configure default route on router HQ : ipv6 unicast-routing
ipv6 route ::/0 2001:DB6:B:B1B2::1
2-advertise this route under ospfv3
Ipv6 router ospf 100
3-fix adjacency problem if a area mismatches
We need to enter in s1/6
Ipv6 ospf 100 area 0
Answer: A

NEW QUESTION: 3
How many bits does an MPLS label field have?
A. 0
B. 1
C. 2
Answer: A

NEW QUESTION: 4
You have two tables: CustTable and CustTrans.
CustTrans has a foreign key relation with CustTable on the "AccountNum" field. Multiple
CustTrans records refer to a single CustTable record. Each CustTrans record can refer to a single CustTable record.
You want to write code to display records of customers and their corresponding transactions. You need to display the following fields:
AccountNum from CustTable table
CustGroup from CustTable table
AmountCur from CustTrans table
Finally, you want to select only the approved transactions. An approved transaction is a
CustTrans record where the value of the Approved field is NoYes::Yes.
You need to choose the data that meets these requirements.
Which select statement should you use?
A. CustTable custTable;
CustTrans custTrans;
while select: AccountNum, CustGroup from custTable
exists join AmountCur -from custTrans
where custTrans.AccountNum == custTable.AccountNum
& & custTrans-Approved == NoYes::Yes
{
// do work
}
B. CustTable custTable;
CustTrans custTrans;
while select AccountNum, CustGroup from custTable
where custTrans .AccountNum == custTable. AccountNum
join AmountCust -from custTrans where custTrans.Approved == NoYes:;Yes
{
// do work
}
C. CustTable custTable;
CustTrans custTrans;
while select: AccountNum, CustGroup -From custTable
join AmountCur -from custTrans
where custTrans.AccountNum == custTable.AccountNum
& & custTrans.Approved == NoYes::Yes
{
// do work
}
D. CustTable custTable;
CustTrans custTrans;
while select AccountNum, CustGroup, AmountCur -from custTable
join custTrans
where custTrans-AccountNum == custTable.AccountNum
& & custTrans.Approved == NoYes::Yes
{
// do work
}
Answer: C